18. Book 6 - Derivation of General Formula for Constants of the Cosmology and Quantum Mechanics - part I.
On 22 September 2017 AD, the feast of St Maurice.
Andrew Yanthar-Wasilik
We are finding General Formula for Equations from the previous book, "Book 5 Integer Formula for Dimensionless Coupling Constants of Fundamental Forces".
All Coupling Constants use the same equations, from which constants can be calculated.
✠Part A of the equation (A/B)C
Integer Formula for fine structure constant alpha, αE, ruling electromagnetic force is
A16 = ( C0)(24 ⁄ 24)
Integer Formula for the weak force, αW, ruling force of decays is
A17 = ( C0)(27 ⁄ 24)
Integer Formula for the strong nuclear force, αS, ruling quarks, and nucleons is
A1 = ( C0)( − 21 ⁄ 24)
From this partial sequence can be obtained a complete sequence.
At n=8, there is an axis of symmetry. Axis at n=8 divide (as it will be shown on the Graphs of the Function) values between Real and Complex. This can be achieved only when the denominator equals 24.
For n=8, the nominator equals 0.
For an explanation of how to find formulae for some sequences, see the webpage of Brian Kell(1)
So we have in the first-row number of a constant, in the second-row value of the exponent of "A,"
and in the third row, the difference between the two adjoining values of the exponent “A”.
n = 11 12 13 14 15 16 17
E(n) = (9)/(24) (12)/(24) (15)/(24) (18)/(24) (21)/(24) (24)/(24) (27)/(24)
Δ(E(n)) = (3)/(24) (3)/(24) (3)/(24) (3)/(24) (3)/(24) (3)/(24)
Constant difference between the values of the Exponents Δ(E(n)) = (3)/(24) and this is the slope ( ((Δy)/(Δx))= a ) of the function (y = a*x + b) we are trying to find. Y-intercept equals b. Y-intercept is at C0 and equals b = -(24)/(24).
So, the exponent can be written as a linear function:
y = ((3)/(24))*x + (-(24)/(24)) = (3*x − 24)/(24) = (x − 8)/(8)
Now, the “A” part of the equation can be written as:
✠Ax = ( C0)((x − 8)/(8)) (Eqn. A)
✠Part B
The following sequence is the "B" part of the equation (A/B)C
B16 = ( C16 / ( 8 + 2 * (24/24) ) )(88 ⁄ 24)
B17 = ( C17 / ( 9 + 2 * ( 24/27 ) ) )(99 ⁄ 24)
B1 = ( C1 / ( -7 + 2 * ( -24/21 ) ) )( − 77 ⁄ 24)
Now, taking under consideration the Exponent part - it can be seen that this sequence is the one in "A" multiplied by a factor of 11, giving:
n = 6 7 8 9 10 11
E (n ) = -(22)/(24) -(11)/(24) (0)/(24) (11)/(24) (22)/(24) (33)/(24)
Δ(E(n)) = (11)/(24) (11)/(24) (11)/(24) (11)/(24) (11)/(24)
Slope, a = (Δy)/(Δx) = (11)/(24)
Y-intercept, at C0, equals b = -(88)/(24)
And the formula for the Exponent EB sequence is:
EB= ((11*x − 88)/(24))
The sequence of the base of the power is:
Constant C16 is ( 8 + 2 * (24/24)
Constant C17 is ( 9 + 2 * ( 24/27 )
Constant C1 is ( -7 + 2 * ( -24/21 )
It can be seen that in the 2 * d part, the “d” equals to reciprocal of the value of the exponent from part A, which we calculated right at the beginning so that this sequence will be equal to:
EpartB = 2 * ((8)/(x − 8)) = ((16)/(x − 8))
Remaining factors from the sum:
8, 9, -7 gives sequence = (x-8)
So, the base of the power equals:
Base of the power = (x-8) + ((16)/(x − 8)) = (x2 − 16x + 80)/(x − 8)
If we take the reciprocal of this function, we will have the product of Cx, and this reciprocal is raised to the Exponent EB. Constants in the nominator of the base of the power C16, C17, and C1 are just the number of the constant, "n", which we replaced by "x", and each constant can be calculated from the formula from "Book 1".
Cx = ( C0) ( π/ e )x (Eqn. I)
The formula for a sequence of the part "B" is then:
✠Bx = {[(C0)(π ⁄ e)x][(x − 8)/(x2 − 16x + 80)]}[(11x − 88)/(24)] (Eqn. B)
✠Part C of the equation (A/B)C
The Exponents of the equation (A/B)C are:
The exponent of the constant C16 is ( C16 ) * (8/24)
The exponent of the constant C17 is ( C17 ) * (9/24)
The exponent of the constant C1 is ( C1 ) * (-7/24)
The sequence : -(7)/(24),..., (8)/(24), (9)/(24),... has an equation equal to ((1)/(3)) of the first one in this article, i.e.,
yc = ((1)/(3)) * ( (x − 8)/(8) ) = (x − 8)/(24)
And CEx = ( C0) ( π/ e )x is the same as Eqn. I
(It should be Cx instead of CEx. However, that would be mixed up with the final result.)
Product of ( CEx) and ( yc = (x − 8)/(24) ) is the Exponent Cxwe are looking for:
✠Cx = ( ( C0) ( π/ e )x ) * ((x − 8)/(24)) (Eqn. C)
And the final result of Exponent Main, ExpM is ExpM = ( A / B )C
Substituting Equations A, B, C, and we get the long formula for ExpM, which is way too long to write; therefore, I will use parts A, B, C of the Equation
ExpM = ( A / B )C (Eqn. EM)
In part II, I will derive the General Formula for any value of the constant alpha and similar to alpha.
Andrew Yanthar-Wasilik
(1)Brian Kell, CMU
Next article (part II) >>> 19. Book 6 - Derivation of General Formula for Constants of the Cosmology and Quantum Mechanics - part II
Return to Syllabus >>> 132. Syllabus of the course – “Voyage through God’s Universe (Cosmos and beyond) according to St. Hildegard von Bingen and others, with the help of Mathematics, Cosmology and Quantum Mechanics."
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